Interior Angles Of A Polygon Sum

Sum of the interior angles of a polygon 180 n 2 degrees interior angles of a polygon formula the interior angles of a polygon always lie inside the polygon.

Interior angles of a polygon sum. Imagine walking round the outside of a polygon. The sum of the measures of the interior angles of a polygon with n sides is n 2 180. Sum of interior angles of n sided polygon n x 180 360 n 2 x 180 method 4 the point p chosen may not be on the vertex side or inside the polygon.

That is interior angle exterior angle 180 160 exterior angle 180 exterior angle 20. If you count one exterior angle at each vertex the sum of the measures of the exterior angles of a polygon is always 360. So it d be 18 000 degrees for the interior angles of a 102 sided polygon.

So it s going to be 100 times 180 degrees which is equal to 180 with two more zeroes behind it. In a regular polygon all the interior angles measure the same and hence can be obtained by dividing the sum of the interior angles by the number of sides. Sum of interior angles n 2 180 each angle of a regular polygon n 2 180 n.

By the time you return to your starting point you will have completed one full turn. The sum of the exterior angles of a polygon is 360. Sum of all the interior angles of a polygon is equal to the product of a straight angle and two less than the number of sides of the polygon.

In order to find the measure of a single interior angle of a regular polygon a polygon with sides of equal length and angles of equal measure with n sides we calculate the sum interior angles or n 2 180 and then divide that sum by the number of sides or n. In any polygon the sum of an interior angle and its corresponding exterior angle is 180. After examining we can see that the number of triangles is two less than the number of sides always.

Each interior angle of a regular polygon measures 160. Sum of interior angles p 2 180. The measure of each interior angle of an equiangular n gon is.